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Author Topic: Xmas Competition -50$ prize  (Read 2331 times)

Offline Hatchy

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Re: Xmas Competition -50$ prize
« Reply #15 on: December 23, 2023, 09:47:03 PM »
Seems like my eyes are shaking but I will say I am seeing 18.
But what more?
I still recheck again and I saw 24 how come, does it mean the more i look the less I see 🙄
Lol, the more you look the less you see  ;D try counting the triangles without repeating any triangle🤐

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Re: Xmas Competition -50$ prize
« Reply #15 on: December 23, 2023, 09:47:03 PM »

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Offline Mbah Jenggot

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Re: Xmas Competition -50$ prize
« Reply #17 on: December 24, 2023, 07:08:35 AM »
A small Xmas competition, give the right answer and win 50$ worth of a Altt token available on dex.
(amount to be purchased from dex before transfer)



ends

6X4 = 24 in tree
10 in star
total 34 triangels
« Last Edit: December 24, 2023, 07:17:04 AM by Mbah Jenggot »



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Re: Xmas Competition -50$ prize
« Reply #20 on: December 24, 2023, 10:10:04 AM »


This puzzle can have many answers. Starting with the hint in the question. Here triangle is in singular, so how many triangle? One.

Then the word "triangle" is a triangle of some kind, so it can be added to the number of each variant, I will add it in brackets.

Then we can count only triangles not crossed with anything, then there are 10 in the star, three in the tree and one in AltcoinsTalks.com line and one in the logo, totally 15 (16).

Then we can count triangles considering that borders are just borders. And this will be my main guess. Then the star has 10, the tree has 24 and one in AltcoinsTalks.com line and one in the logo, totally 36 (37).

Then we can consider that borders can hide a triangle on the backside. If we count only the ones which don't have crossing with other lines, then there will be additionally one triangle in the tree and one in the logo.

Then we can see all back triangles surrounding the inner ones. Then there are the same 24 additional triangles in the free, 10 in the star, one in the line AltcoinsTalks.com and one in the logo. So up to 72 (73).

And two last small things: I looked at the k letter in the logo and thought if it can have triangles also, but there are opened spases between the lines, so these geometric figures are hardly triangles; I also thought if a star hides some part of triangles in the top of the tree to make them non-triangles, but the picture is too small and I thought it can hardly be a trick.
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Offline Ambatman

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Re: Xmas Competition -50$ prize
« Reply #21 on: December 24, 2023, 10:34:18 AM »


Then we can see all back triangles surrounding the inner ones. Then there are the same 24 additional triangles in the free, 10 in the star, one in the line AltcoinsTalks.com and one in the logo. So up to 72 (73).

I think the question is based only on the Xmas image.
If it isn't then the question would be more complicated than it seems.
Lol but Lord are physicist built different
I saw only the image and you have taken other aspects into consideration.
Hopefully the answer is 35
I think those that picked 34 forgot to add the bigger triangle.
Seeing others answers and their explanation made me remember why games like this are fun.

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Re: Xmas Competition -50$ prize
« Reply #21 on: December 24, 2023, 10:34:18 AM »


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Re: Xmas Competition -50$ prize
« Reply #22 on: December 24, 2023, 11:31:59 AM »
If it isn't then the question would be more complicated than it seems.

If it wasn't more complicated, then it was too simple. All answers about the star and the divided triangle are widely known: 10 and 24. So main thing is what are the tricks. ;D
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Re: Xmas Competition -50$ prize
« Reply #23 on: December 24, 2023, 12:37:57 PM »
If it wasn't more complicated, then it was too simple. All answers about the star and the divided triangle are widely known: 10 and 24. So main thing is what are the tricks. ;D
Maybe Admin is brimming with Christmas spirit and feels like playing Santa :)
25 not 24
Did u count the main triangle?

Well if we doing tricks then the question said "How many triangle you see" not "how many triangle are here"  this means any answer is correct so admin is compensating everyone ;D

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Re: Xmas Competition -50$ prize
« Reply #24 on: December 24, 2023, 12:46:31 PM »
25 not 24
Did u count the main triangle?

24. You are counting the main one twice, when you count the bottom line of triangles and then once more, but it is the same triangle, so no need to count it twice. :)

Well if we doing tricks then the question said "How many triangle you see" not "how many triangle are here"  this means any answer is correct so admin is compensating everyone ;D

Who knows? There can be many possible unexpected tricks. ;D
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Re: Xmas Competition -50$ prize
« Reply #25 on: December 24, 2023, 03:16:43 PM »
Microsoft's AI says the answer is 52. They can count triangles on an image now. crazy  :o
Prompt used:
Quote
How many triangles can you can count on this image https://imgur.com/f2G6Cx4

Quote
This is a tricky question, as there are different ways to count triangles in a complex figure. One possible method is to use the formula n(n+2)/8, where n is the number of sides of the polygon. This formula works for regular polygons that are divided into congruent triangles by drawing all the diagonals from one vertex. However, this formula does not work for irregular polygons or polygons that have more than one set of diagonals.

In this case, the image shows an irregular hexagon that has two sets of diagonals. Therefore, we need to count the triangles manually. One way to do this is to label the vertices of the hexagon as A, B, C, D, E, F and the intersection points of the diagonals as G, H, I, J, K, L. Then, we can list all the possible triangles that can be formed by three points. For example, ABC, ABD, ABE, ABF, ABG, ABH, ABI, ABJ, ABK, ABL are some of the triangles that have A and B as two of their vertices. We can repeat this process for all the other pairs of vertices and eliminate any duplicates. Alternatively, we can group the triangles by their size or shape and count them accordingly. For example, there are 12 small equilateral triangles, 6 medium isosceles triangles, 6 large isosceles triangles, and 6 scalene triangles in the figure.

Using either method, we can find that there are 30 triangles in the image. However, this is not the final answer, as there are also some hidden triangles that are formed by combining smaller triangles. For example, AGL, BHK, CIJ, DFK, EGL, FHI are some of the hidden triangles that are formed by joining two small equilateral triangles. We can also find hidden triangles that are formed by joining three or four smaller triangles. For example, AFK, BIL, CDJ, AEJ, BFK, CIL are some of the hidden triangles that are formed by joining three small equilateral triangles. Similarly, ADL, BEK, CFJ are some of the hidden triangles that are formed by joining four small equilateral triangles.

To find the total number of hidden triangles, we can use another formula: 2^(n-1) - n, where n is the number of sides of the polygon. This formula works for polygons that are divided into congruent triangles by drawing all the diagonals from one vertex, and it gives the number of triangles that are formed by combining two or more smaller triangles. However, this formula also does not work for irregular polygons or polygons that have more than one set of diagonals. Therefore, we need to count the hidden triangles manually as well.

Using either method, we can find that there are 22 hidden triangles in the image. Therefore, the final answer is 30 + 22 = 52 triangles in the image. This is one possible solution, but there may be other ways to count the triangles or other hidden triangles that are not accounted for. Therefore, the answer may vary depending on how one defines a triangle and how one counts them.


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Re: Xmas Competition -50$ prize
« Reply #26 on: December 24, 2023, 03:53:28 PM »
Microsoft's AI says the answer is 52. They can count triangles on an image now. crazy  :o

Can it? I'm trying to find that "irregular hexagon" which it named and can't see it. So it looks more like an essay about the triangle counting than a real triangle counting. ;D
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Re: Xmas Competition -50$ prize
« Reply #27 on: December 24, 2023, 04:33:30 PM »
Quote from: Jokers
24. You are counting the main one twice, when you count the bottom line of triangles and then once more, but it is the same triangle, so no need to count it twice. :)
[/quote

Lord!!!! Lol you are right.
Just recounted and saw my mistake.
Sigh guess I'm out
Look forward to another contest with similar or better energy

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Re: Xmas Competition -50$ prize
« Reply #28 on: December 24, 2023, 04:48:14 PM »
I wasn't aware that we could edit our post so created a new one accidentally.
So let me modify it and use it as an opportunity to say
MERRY XMAS(in advance) EVERYONE

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Re: Xmas Competition -50$ prize
« Reply #29 on: December 25, 2023, 12:05:02 PM »
24 in the green zone, and 10 in the star. In total 34
Correct, Winner
At your service.

 

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