The process of selecting the winner will be done by the transaction hash
I will send 1 ALTT to burn address after this post.
the transaction hash will be similar to this one:
for example:https://bscscan.com/tx/0x8f9ae5f0d2b9dd25195f71fd6c70e72cc35a9c2cfd703bb05e35985b7f77a1e2or hash: 0x8f9ae5f0d2b9dd25195f71fd6c70e72cc35a9c2cfd703bb05e35985b7f77a
1e
2I will take the last 2 digits, in this example case
12The winner will be announced in my next post, with the trx hash that will be done.
this post will not be modified or edited.
thus tickets:Bliznec:5 > 01 to 05
Wiseman:10> 06 to 15
mnixxo.crypto: 6 > 16 to 21
Learn Bitcoin: 10 > 22 to 31
kulkhan:6 > 32 to 37
tvplus006:10 > 38 to 47
examplens:10 > 48 to 57
hugeblack: 5 > 58 to 62
bitmover : 5 > 63 to 67
dkbit98 : 5 > 68 to 72
What happens if last 2 digits are 00 or above 72 ?
I burn again. 1 ALTT
PS: first try: I will burn 1002 ALTT , i am adding 1001 ALTT to our ex-president 6th ticket because he did the math wrong

(my mistake, i was not clear enough)